-16t^2-96t=t

Solution for -16t^2-96t=t equation:

-16t^2-96t=t

We move all terms to the left:

-16t^2-96t-(t)=0

We add all the numbers together, and all the variables

-16t^2-97t=0

a = -16; b = -97; c = 0;
Δ = b2-4ac
Δ = -972-4·(-16)·0
Δ = 9409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9409}=97$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-97)-97}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-97)+97}{2*-16}=\frac{194}{-32}
=-6+1/16
$